A satellite is launched into a circular orbit of radius ' R ' around the earth. A second statellite is launched into an orbit of radius 1.03 R . The time period of revolution of the second satellite is larger than the first one approximately by :-
- (A)
- (B)✓ Correct
- (C)
- (D)
Answer: (B)
Solution
Kepler's third law gives . Taking logarithmic differentials for small changes:
Here (since the new radius is ):
The percentage increase in time period is .
Here (since the new radius is ):
The percentage increase in time period is .
JEE Main · 2025 · 24 Jan 2025 · Shift 1 · Single correct option