Match List-I with List-II **List-I (Tetrahedral Complex)** (A) $\mathrm{TiCl}_{4}$ (B) $\left[\mathrm{FeO}_{4}\right]^{2-}$ (C) $\left[\mathrm{FeCl}_{4}\right]^{-}$ (D) $\left[\mathrm{CoCl}_{4}\right]^{2-}$ **List-II (Electronic configuration)** (I) $\mathrm{e}^{2}, \mathrm{t}_{2}^{0}$ (II) $\mathrm{e}^{4}, \mathrm{t}_{2}^{3}$ (III) $\mathrm{e}^{0}, \mathrm{t}_{2}^{0}$ (IV) $\mathrm{e}^{2}, \mathrm{t}_{2}^{3}$ Choose the correct answer from the option given below:

: Ti is , — configuration . : O is , so Fe is , ; in a tetrahedral field ( below ) the two electrons fill first — . : Fe is , ; tetrahedral splitting is small, so this is high-spin — . : Co is , , high-spin tetrahedral — . So (A)- , (B)- , (C)- , (D)- .

JEE Main · 2024 · 06 Apr 2024 · Shift 2 · Coordination Compounds

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Match List-I with List-II

List-I (Tetrahedral Complex)

(A)

TiCl_{4}

(B)

[FeO_{4}]^{2 -}

(C)

[FeCl_{4}]^{-}

(D)

[CoCl_{4}]^{2 -}

List-II (Electronic configuration)

(I)

e^{2}, t_{2}^{0}

(II)

e^{4}, t_{2}^{3}

(III)

e^{0}, t_{2}^{0}

(IV)

e^{2}, t_{2}^{3}

Choose the correct answer from the option given below:

Answer: A → III, B → I, C → IV, D → II

Solution

TiCl_{4}

: Ti is

+ 4

d^{0}

— configuration

e^{0}, t_{2}^{0}

[FeO_{4}]^{2 -}

: O is

- 2

, so Fe is

+ 6

d^{2}

; in a tetrahedral field (

e

below

t_{2}

) the two electrons fill

e

first —

e^{2}, t_{2}^{0}

[FeCl_{4}]^{-}

: Fe is

+ 3

d^{5}

; tetrahedral splitting is small, so this is high-spin —

e^{2}, t_{2}^{3}

[CoCl_{4}]^{2 -}

: Co is

+ 2

d^{7}

, high-spin tetrahedral —

e^{4}, t_{2}^{3}

. So (A)-

e^{0} t_{2}^{0}

, (B)-

e^{2} t_{2}^{0}

, (C)-

e^{2} t_{2}^{3}

, (D)-

e^{4} t_{2}^{3}

JEE Main · 2024 · 06 Apr 2024 · Shift 2 · Match the columns

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JEE Main · 2024 · 06 Apr 2024 · Shift 2 · Coordination Compounds

Solution

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