Given below are two statements: Statement I: \(\mathrm{PF}_{5}\) and \(\mathrm{BrF}_{5}\) both exhibit \(\mathrm{sp}^{3} \mathrm{~d}\) hybridisation. Statement II: Both \(\mathrm{SF}_{6}\) and \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}\) exhibit \(\mathrm{sp}^{3} \mathrm{~d}^{2}\) hybridisation. In the light of the above statements, choose the correct answer from the options given below:

(C) Both Statement I and Statement II are false

(A) Statement I is true but Statement II is false

(B) Both Statement I and Statement II are true

(D) Statement I is false but Statement II is true

JEE Main · 2024 · 06 Apr 2024 · Shift 2 · Chemical Bonding and Molecular Structure

Given below are two statements:

Statement I:

PF_{5}

and

BrF_{5}

both exhibit

sp^{3} d

hybridisation.
Statement II: Both

SF_{6}

and

[Co (NH_{3})_{6}]^{3 +}

exhibit

sp^{3} d^{2}

hybridisation.
In the light of the above statements, choose the correct answer from the options given below:

Answer: (C)

PF_{5}

s p^{3} d

hybridised, but

BrF_{5}

(square pyramidal, one lone pair on Br) is

s p^{3} d^{2}

, not

s p^{3} d

— statement I is false.

SF_{6}

is indeed

s p^{3} d^{2}

, but

[Co(NH_{3})_{6}]^{3 +}

is a strong-field, inner-orbital octahedral complex using

(n - 1) d

orbitals, i.e.

d^{2} s p^{3}

, not

s p^{3} d^{2}

— statement II is also false. Both statements are false.

JEE Main · 2024 · 06 Apr 2024 · Shift 2 · Single correct option