JEE Main · 2024 · 04 Apr 2024 · Shift 1 · Practical and Analytical Chemistry

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Only 2 mL of KMnO₄ solution of unknown molarity is required to reach the end point of a titration of 20 mL of oxalic acid (2 M) in acidic medium. The molarity of KMnO₄ solution should be ____ M.

Answer: 8

Solution

In acidic medium

2 Mn O_{4}^{-} + 5 C_{2} O_{4}^{2 -} + 16 H^{+} \to 2 M n^{2 +} + 10 C O_{2} + 8 H_{2} O

. Equivalents balance at the end point. Oxalic acid (n-factor 2) supplies

2 \times 20 \times 2 = 80

meq.

KMn O_{4}

has n-factor 5, so

M_{KMn O_{4}} \times 2 \times 5 = 80 \Rightarrow M = 8

M. (An 8 M permanganate is physically unrealisable, but it is the stoichiometric answer the data demands.)

JEE Main · 2024 · 04 Apr 2024 · Shift 1 · Integer answer

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