Which is the final product (major) 'A' in the given reaction?
(A)(see structure)
(B)(see structure)
(C)(see structure)✓ Correct
(D)(see structure)
Answer: (C)
Solution
The reaction involves the addition of HCl to an alkene in the presence of peroxide. Under peroxide conditions (anti-Markovnikov addition), the chlorine adds to the less substituted carbon. However, the product shown in option (3) is a geminal dichloride (two chlorines on the same carbon), which forms when excess HCl reacts with the alkene.
The mechanism proceeds through:
Initial anti-Markovnikov addition of HCl to form a chloroalkane
Further reaction with HCl to form the geminal dichloride
The final product is the tertiary geminal dichloride shown in option (3), where both chlorine atoms are attached to the same carbon bearing two methyl groups.
JEE Main · 2021 · 24 Feb 2021 · Shift 1 · Single correct option