Let ABC be an equilateral triangle. A new triangle is formed by joining the middle points of all sides of the triangle ABC and the same process is repeated infinitely many times. If P is the sum of perimeters and Q is the sum of area of all the triangles formed in this process, then
(A)P2=63Q
(B)P2=363Q✓ Correct
(C)P=363Q2
(D)P=723Q
Answer: (B)
Solution
With initial side a, successive triangles (formed by joining midpoints) have sides a,a/2,a/4,…. Perimeter sum: P=3a(1+21+41+⋯)=3a⋅2=6a. Area sum: Q=43a2(1+41+161+⋯)=43a2⋅34=3a2, so a2=3Q. Then P2=36a2=363Q.
JEE Main · 2024 · 06 Apr 2024 · Shift 2 · Single correct option