If f(x)={x3sin(x1),0,x=0x=0, then(A)f′′(π2)=2π24−π2✓ Correct(B)f′′(0)=0(C)f′′(0)=1(D)f′′(π2)=2π12−π2Answer: (A)Solutionf′(x)=3x2sinx1−xcosx1.f′′(x)=6xsinx1−4cosx1−x1sinx1.At x=π2 (x1=2π): sin2π=1, cos2π=0:f′′(π2)=6⋅π2−0−2π=π12−2π=2π24−π2.JEE Main · 2024 · 06 Apr 2024 · Shift 1 · Single correct option