A particle of mass m and charge q, moving with velocity V enters Region II normal to the boundary as shown in the figure. Region II has a uniform magnetic field B perpendicular to the plane of the paper. The length of the Region II is ℓ. Choose the correct choice(s).
(A)The particle enters Region III only if its velocity V>mqℓB✓ Correct
(B)The particle enters Region III only if its velocity V<mqℓB
(C)Path length of the particle in Region II is maximum when velocity V=mqℓB✓ Correct
(D)Time spent in Region II is same for any velocity V as long as the particle returns to Region I✓ Correct
Answer: (A), (C), (D)
Solution
The particle moves in a circular arc with radius r=qBmV. For the particle to enter Region III, it must traverse the width ℓ, requiring r>ℓ, i.e., V>mqℓB (A is correct). The path length is maximum when the particle just grazes the boundary, i.e., when r=ℓ or V=mqℓB (C is correct). The time spent in Region II for a particle returning to Region I depends only on the angle subtended, which is determined by the geometry, making the time constant for particles that return (D is correct).
JEE Advanced · 2008 · 13 Apr 2008 · Paper 1 · One or more correct options