Dissolving 120 g of urea (mol. wt. 60) in 1000 g of water gave a solution of density . The molarity of the solution is
- (A)1.78 M
- (B)2.00 M
- (C)2.05 M✓ Correct
- (D)2.22 M
Answer: (C)
Solution
Total mass of solution = 1000 + 120 = 1120 g
Total volume of solution = mL = L
Number of moles of urea = mol
Molarity = M
Total volume of solution = mL = L
Number of moles of urea = mol
Molarity = M
JEE Advanced · 2011 · 10 Apr 2011 · Paper 1 · Single correct option