Match the chemical conversions in List I with the appropriate reagents in List II and select the correct answer using the code given below the lists:

| List II | |
|---|---|
| 1. | (i) ; (ii) |
| 2. | NaOEt |
| 3. | Et-Br |
| 4. | (i) ; (ii) |

- (A)P-2, Q-3, R-1, S-4✓ Correct
- (B)P-3, Q-2, R-1, S-4
- (C)P-2, Q-3, R-4, S-1
- (D)P-3, Q-2, R-4, S-1
Answer: (A)
Solution
Matching the conversions with reagents:
P: Elimination reaction (E2) → NaOEt (2)
Q: Williamson ether synthesis → Et-Br (3)
R: Oxymercuration-demercuration (Markovnikov addition) → (i) ; (ii) (1)
S: Hydroboration-oxidation (anti-Markovnikov addition) → (i) ; (ii) (4)
Code: P-2, Q-3, R-1, S-4
P: Elimination reaction (E2) → NaOEt (2)
Q: Williamson ether synthesis → Et-Br (3)
R: Oxymercuration-demercuration (Markovnikov addition) → (i) ; (ii) (1)
S: Hydroboration-oxidation (anti-Markovnikov addition) → (i) ; (ii) (4)
Code: P-2, Q-3, R-1, S-4
JEE Advanced · 2013 · 02 Jun 2013 · Paper 2 · Single correct option