JEE Advanced · 2016 · 22 May 2016 · Paper 2 · Units & Measurement

WhatsApp Email

There are two Vernier calipers both of which have 1 cm divided into 10 equal divisions on the main scale. The Vernier scale of one of the calipers (

C_{1}

) has 10 equal divisions that correspond to 9 main scale divisions. The Vernier scale of the other caliper

(C_{2})

has 10 equal divisions that correspond to 11 main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers

C_{1}

and

C_{2}

, respectively, are

(A)2.85 and 2.82
(B)2.87 and 2.83✓ Correct
(C)2.87 and 2.86
(D)2.87 and 2.87

Answer: (B)

Solution

For

C_{1}

: 10 VSD = 9 MSD, so least count = 0.1 cm

Main scale reading = 2.8 cm, Vernier coincidence = 7

Reading = 2.8 + 7(0.01) = 2.87 cm

For

C_{2}

: 10 VSD = 11 MSD, so 1 VSD = 1.1 MSD

Least count = 1 VSD - 1 MSD = 0.1 MSD = -0.01 cm

Main scale reading = 2.8 cm, Vernier coincidence = 7

Reading = 2.8 + 0.1 - 7(0.01) = 2.83 cm

JEE Advanced · 2016 · 22 May 2016 · Paper 2 · Single correct option

Practise more: all JEE Advanced PYQs on Units & Measurement →

JEE Advanced · 2016 · 22 May 2016 · Paper 2 · Units & Measurement

Solution

More JEE Advanced questions on Units & Measurement