JEE Advanced · 2018 · 20 May 2018 · Paper 1 · Hydrocarbons

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Passage
Treatment of benzene with CO/HCl in the presence of anhydrous followed by reaction with gives compound as the major product. Compound X upon reaction with , followed by heating at 473 K with moist KOH furnishes as the major product. Reaction of with , followed by treatment gives Z as the major product.
Treatment of benzene with CO/HCl in the presence of anhydrous followed by reaction with gives compound as the major product. Compound upon reaction with , followed by heating at 473 K with moist KOH furnishes as the major product. Reaction of with , followed by treatment gives as the major product.

The compound is
  1. (A)(see structure)
  2. (B)(see structure)
  3. (C)(see structure)
    ✓ Correct
  4. (D)(see structure)

Answer: (C)

Solution

The reaction sequence:
  1. Benzene + CO/HCl with gives benzaldehyde (Gattermann-Koch reaction).
  2. Benzaldehyde + gives cinnamic acid (Perkin reaction), which is compound X: .
  3. X + followed by heating with moist KOH at 473 K gives phenylacetylene (decarboxylation and elimination), which is compound Y.

Compound Y is phenylacetylene:

Correct answer: (C)

JEE Advanced · 2018 · 20 May 2018 · Paper 1 · Single correct option

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