JEE Advanced · 2019 · 27 May 2019 · Paper 2 · Waves & Sound

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A musical instrument is made using four different metal strings, 1,2,3 and 4 with mass per unit length and respectively. The instrument is played by vibrating the strings by varying the free length in between the range and . It is found that in string-1 at free length and tension the fundamental mode frequency is .

List-I gives the above four strings while list-II lists the magnitude of some quantity.

List-I
(I) String-1
(II) String-2
(III) String-3
(IV) String-4

List-II
(P) 1
(Q) 1/2
(R)
(S)
(T) 3/16
(U) 1/16

If the tension in each string is , the correct match for the highest fundamental frequency in units will be,
  1. (A)I→P, II→R, III→S, IV→Q✓ Correct
  2. (B)I→P, II→Q, III→T, IV→S
  3. (C)I→Q, II→S, III→R, IV→P
  4. (D)I→Q, II→P, III→R, IV→T

Answer: (A)

Solution

For fundamental mode, the frequency is:


For string 1: → (P) = 1

For string 2: → (R)

For string 3: → (S)

For string 4: → (Q)

Therefore: I→P, II→R, III→S, IV→Q

JEE Advanced · 2019 · 27 May 2019 · Paper 2 · Single correct option

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