Which of the following statement(s) is(are) true ?
(A)Oxidation of glucose with bromine water gives glutamic acid
(B)The two six-membered cyclic hemiacetal forms of D-(+)-glucose ard called anomers✓ Correct
(C)Hydrolysis of sucrose gives dextrorotatory glucose and laevorotatory fructose✓ Correct
(D)Monosaccharides cannot be hydrolysed to give polyhydroxy aldehydes and ketones✓ Correct
Answer: (B), (C), (D)
Solution
(A) FALSE: Oxidation of glucose with bromine water gives gluconic acid (a carboxylic acid), not glutamic acid (an amino acid).
(B) TRUE: The α and β forms of D-glucose are anomers — they differ only in configuration at the anomeric carbon (C-1) in the cyclic hemiacetal form.
(C) TRUE: Sucrose hydrolysis (inversion) gives D-(+)-glucose (dextrorotatory) and D-(-)-fructose (laevorotatory). The mixture is laevorotatory overall.
(D) TRUE: Monosaccharides are the simplest sugars and cannot be hydrolyzed further. They already are polyhydroxy aldehydes or ketones in their open-chain form.
JEE Advanced · 2019 · 27 May 2019 · Paper 1 · One or more correct options
