A horizontal force F is applied at the center of mass of a cylindrical object of mass m and radius R, perpendicular to its axis as shown in the figure. The coefficient of friction between the object and the ground is μ. The center of mass of the object has an acceleration a. The acceleration due to gravity is g. Given that the object rolls without slipping, which of the following statement(s) is(are) correct?
(A)For the same F, the value of a does not depend on whether the cylinder is solid or hollow
(B)For a solid cylinder, the maximum possible value of a is 2μg✓ Correct
(C)The magnitude of the frictional force on the object due to the ground is always μmg
(D)For a thin-walled hollow cylinder, a=2mF✓ Correct
Answer: (B), (D)
Solution
For rolling without slipping: F−f=maC and fR=ICα with aC=αR.
Combining: aC=m+IC/R2F and f=m+IC/R2FIC/R2.
For a thin-walled hollow cylinder, IC=mR2, so aC=2mF ✓ (option D).
For a solid cylinder, IC=2mR2. The friction constraint is f=R2ICaC≤μmg, giving aC≤ICμmgR2=mR2/2μmgR2=2μg ✓ (option B).
Option (A) is incorrect because aC depends on IC, which differs for solid vs hollow cylinders.
Option (C) is incorrect because f=m+IC/R2FIC/R2, not always μmg.
JEE Advanced · 2021 · 03 Oct 2021 · Paper 1 · One or more correct options