JEE Advanced · 2021 · 03 Oct 2021 · Paper 2 · Compounds Containing Nitrogen

Reaction of

x g

of Sn with HCl quantitatively produced a salt. Entire amount of the salt reacted with

yg

of nitrobenzene in the presence of required amount of HCl to produce 1.29 g of an organic salt (quantitatively).
(Use Molar masses (in

g mol^{- 1}

) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively).

The value of

x

is ____.

Answer: 3.57

Solution

Sn reacts with HCl to form

SnCl_{2}

. This reduces nitrobenzene to aniline, which forms anilinium chloride (

C_{6} H_{5} NH_{3}^{+} Cl^{-}

) as the organic salt. Molar mass of anilinium chloride = 6(12) + 8(1) + 14 + 35 = 129 g/mol. Moles of organic salt = 1.29/129 = 0.01 mol. The reduction of nitrobenzene requires 3 moles of Sn per mole of nitrobenzene (

C_{6} H_{5} NO_{2} + 3 Sn + 7 HCl \to C_{6} H_{5} NH_{3}^{+} Cl^{-} + 3 SnCl_{2} + 2 H_{2} O

). So 0.01 mol nitrobenzene requires 0.03 mol Sn. Mass of Sn = 0.03 × 119 = 3.57 g.

JEE Advanced · 2021 · 03 Oct 2021 · Paper 2 · Numerical answer

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JEE Advanced · 2021 · 03 Oct 2021 · Paper 2 · Compounds Containing Nitrogen

Solution

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