Let . If A contains exactly one positive integer n, then the value of n is
Answer: 281
Solution
Let .
Note that and .
So:
Multiplying numerator and denominator by the conjugate:
For A to be a positive integer, the imaginary part must be zero:
This gives and .
The real part becomes:
Answer: 281
Note that and .
So:
Multiplying numerator and denominator by the conjugate:
For A to be a positive integer, the imaginary part must be zero:
This gives and .
The real part becomes:
Answer: 281
JEE Advanced · 2023 · 04 Jun 2023 · Paper 1 · Integer answer