JEE Advanced · 2024 · 26 May 2024 · Paper 2 · Polymers

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An organic compound P with molecular formula decolorizes bromine water and also shows positive iodoform test. P on ozonolysis followed by treatment with gives Q and R. While compound Q shows positive iodoform test, compound does not give positive iodoform test. and on oxidation with pyridinium chlorochromate (PCC) followed by heating give S and T, respectively. Both S and T show positive iodoform test.

Complete copolymerization of 500 moles of and 500 moles of gives one mole of a single acyclic copolymer .
[Given, atomic mass : ]

The molecular weight of U is ____.

Answer: 93018

Solution

From the previous analysis:
  • Q: , molecular weight = 48 + 8 + 48 = 104
  • R: , molecular weight = 60 + 10 + 48 = 118

Condensation polymerization of 500 moles Q + 500 moles R forms 1 mole of copolymer U (PHBV - poly(hydroxybutyrate-co-hydroxyvalerate)).

In condensation polymerization, each linkage releases one water molecule (18 g/mol).
Total linkages = 500 + 500 - 1 = 999

Molecular weight of U:


JEE Advanced · 2024 · 26 May 2024 · Paper 2 · Numerical answer

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