Four identical thin, square metal sheets, S1,S2,S3 and S4, each of side a are kept parallel to each other with equal distance d(≪a) between them, as shown in the figure. Let C0=ε0a2/d, where ε0 is the permittivity of free space.
Match the quantities mentioned in List-I with their values in List-II and choose the correct option.
List-I
(P)
The capacitance between S1 and S4, with S2 and S3 not connected, is
(Q)
The capacitance between S1 and S4, with S2 shorted to S3, is
(R)
The capacitance between S1 and S3, with S2 shorted to S4, is
(S)
The capacitance between S1 and S2, with S3 shorted to S1, and S2 shorted to S4, is
List-II
(1)
C0
(2)
C0/2
(3)
C0/3
(4)
3C0/2
(5)
2C0
(A)P→3;Q→2;R→4;S→5
(B)P→2;Q→3;R→2;S→1
(C)P→3;Q→2;R→4;S→1✓ Correct
(D)P→3;Q→2;R→2;S→5
Answer: (C)
Solution
(P) With S2 and S3 floating, three capacitors in series: Ceq=3C0 (P→3). (Q) With S2 shorted to S3, two capacitors in series: Ceq=2C0 (Q→2). (R) With S2 shorted to S4, the configuration gives Ceq=23C0 (R→4). (S) With S3 shorted to S1 and S2 shorted to S4, the effective capacitance is C0 (S→1).
JEE Advanced · 2024 · 26 May 2024 · Paper 1 · Single correct option