JEE Main · 2026 · 08 Apr 2026 · Shift 2 · Kinematics

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Two identical bodies, projected with the same speed at two different angles cover the same horizontal range R. If the time of flight of these bodies are 5 s and 10 s, respectively, then the value of

R

is ____ m. (Take

g = 10 m / s^{2}

)

(A)250✓ Correct
(B)25
(C)500
(D)125

Answer: (A)

Solution

Equal ranges for the same launch speed occur for complementary angles, and the two times of flight are

T_{1} = \frac{2 u sin θ}{g}

and

T_{2} = \frac{2 u cos θ}{g}

. Multiplying,

T_{1} T_{2} = \frac{4 u ^{2} sin θ cos θ}{g ^{2}} = \frac{2}{g} \cdot \frac{u ^{2} sin 2 θ}{g} = \frac{2 R}{g}

. Hence

R = \frac{g T _{1} T _{2}}{2} = \frac{10 \times 5 \times 10}{2} = 250 m

. The horizontal range is

250 m

JEE Main · 2026 · 08 Apr 2026 · Shift 2 · Single correct option

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