JEE Main · 2026 · 06 Apr 2026 · Shift 1 · Permutations and Combinations

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The number of 4-letter words, with or without meaning, each consisting of two vowels and two consonants that can be formed from the letters of the word INCONSEQUENTIAL, without repeating any letter, is:

(A)2670
(B)2840
(C)2920
(D)3600✓ Correct

Answer: (D)

Solution

In INCONSEQUENTIAL the distinct vowels are I, E, O, A, U (five) and the distinct consonants are N, C, S, Q, T, L (six). A four-letter word with two distinct vowels and two distinct consonants is built by choosing the vowels in

(2 5) = 10

ways, the consonants in

(2 6) = 15

ways, and arranging the four chosen letters in

4! = 24

ways. The number of such words is

10 \times 15 \times 24 = 3600

JEE Main · 2026 · 06 Apr 2026 · Shift 1 · Single correct option

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