Which of the following sequence of hybridisation, geometry and magnetic nature are correct for the given coordination compounds ? A. \([\mathrm{NiCl}_{4}]^{2-}-\mathrm{sp}^{3}\), tetrahedral, paramagnetic B. \([\mathrm{Ni}(\mathrm{NH}_{3})_{6}]^{2+}-\mathrm{sp}^{3} \mathrm{~d}^{2}\), octahedral, paramagnetic C. \([\mathrm{Ni}(\mathrm{CO})_{4}]-\mathrm{sp}^{3}\), tetrahedral, paramagnetic D. \([\mathrm{Ni}(\mathrm{CN})_{4}]^{2-}-\mathrm{dsp}^{2}\), square planar diamagnetic Choose the correct answer from the options given below :

JEE Main · 2026 · 06 Apr 2026 · Shift 2 · Coordination Compounds

Which of the following sequence of hybridisation, geometry and magnetic nature are correct for the given coordination compounds ?
A.

[NiCl_{4}]^{2 -} - sp^{3}

, tetrahedral, paramagnetic
B.

[Ni (NH_{3})_{6}]^{2 +} - sp^{3} d^{2}

, octahedral, paramagnetic
C.

[Ni (CO)_{4}] - sp^{3}

, tetrahedral, paramagnetic
D.

[Ni (CN)_{4}]^{2 -} - dsp^{2}

, square planar diamagnetic

Choose the correct answer from the options given below :

Answer: (D)

[NiC l_{4}]^{2 -}

has

N i^{2 +}

(

d^{8}

) with weak-field chloride, giving

s p^{3}

hybridisation, a tetrahedral shape and two unpaired electrons, so it is paramagnetic.

[Ni (N H_{3})_{6}]^{2 +}

s p^{3} d^{2}

, octahedral and, with two unpaired electrons, paramagnetic.

[Ni (CN)_{4}]^{2 -}

has strong-field cyanide pairing the electrons to give

d s p^{2}

hybridisation, a square planar shape and a diamagnetic centre.

[Ni (CO)_{4}]

s p^{3}

and tetrahedral but, with nickel in the zero oxidation state and a paired

d^{10}

set, it is diamagnetic, not paramagnetic, so its listed description fails. The correctly described complexes are

[NiC l_{4}]^{2 -}

[Ni (N H_{3})_{6}]^{2 +}

and

[Ni (CN)_{4}]^{2 -}

JEE Main · 2026 · 06 Apr 2026 · Shift 2 · Single correct option