Given below are two statements : Statement I: \(\mathrm{F}_{2} \mathrm{O}<\mathrm{H}_{2} \mathrm{O}<\mathrm{Cl}_{2} \mathrm{O}\) is the correct trend in terms of bond angle. Statement II : \(\mathrm{SiF}_{4}, \mathrm{SnF}_{4}\) and \(\mathrm{PbF}_{4}\) are ionic in nature. In the light of the above statements, choose the correct answer from the options given below :

(C) Statement I is true but Statement II is false

(A) Both Statement I and Statement II are true

(B) Both Statement I and Statement II are false

(D) Statement I is false but Statement II is true

JEE Main · 2026 · 06 Apr 2026 · Shift 2 · Chemical Bonding and Molecular Structure

Given below are two statements :

Statement I:

F_{2} O < H_{2} O < Cl_{2} O

is the correct trend in terms of bond angle.
Statement II :

SiF_{4}, SnF_{4}

and

PbF_{4}

are ionic in nature.
In the light of the above statements, choose the correct answer from the options given below :

(A)Both Statement I and Statement II are true
(B)Both Statement I and Statement II are false
(C)Statement I is true but Statement II is false✓ Correct
(D)Statement I is false but Statement II is true

Answer: (C)

Solution

The bond angle widens along

F_{2} O (10 3^{\circ}) < H_{2} O (104. 5^{\circ}) < C l_{2} O (11 1^{\circ})

: the strongly electronegative fluorine draws the bonding pairs away from oxygen and narrows the angle, whereas the bulkier, less electronegative chlorine opens it out, so the stated trend is correct and Statement I is true. Among the tetrafluorides

Si F_{4}

is a covalent molecular species, so the claim that

Si F_{4}

Sn F_{4}

and

Pb F_{4}

are all ionic is wrong and Statement II is false. Statement I is true while Statement II is false.

JEE Main · 2026 · 06 Apr 2026 · Shift 2 · Single correct option

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JEE Main · 2026 · 06 Apr 2026 · Shift 2 · Chemical Bonding and Molecular Structure

Solution

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