The curves y=x2−8x and y=−x meet where x2−8x=−x, i.e. x2−7x=0, so x=0 and x=7, with the line above the parabola between them. The area is ∫07[(−x)−(x2−8x)]dx=∫07(7x−x2)dx=[27x2−3x3]07=2343−3343=6343.
JEE Main · 2026 · 06 Apr 2026 · Shift 2 · Single correct option