Given below are two statements : Statement-I : Aluminium upon reaction with NaOH forms \(\left[\mathrm{Al}(\mathrm{OH})_{6}\right]^{3-}\) ion. Statement-II : The geometry of \(\mathrm{ICl}_{4}^{-}, \mathrm{ClO}_{3}^{-}\)and \(\mathrm{IBr}_{2}^{-}\)is square planar, pyramidal and linear respectively. In the light of the above statements, choose the correct answer from the options given below :

(D) Statement-I is false but Statement-II is true.

(A) Both Statement-I and Statement-II are true.

(B) Both Statement-I and Statement-II are false.

(C) Statement-I is true but Statement-II is false.

JEE Main · 2026 · 05 Apr 2026 · Shift 2 · Chemical Bonding and Molecular Structure

Given below are two statements :

Statement-I : Aluminium upon reaction with NaOH forms

[Al (OH)_{6}]^{3 -}

ion.
Statement-II : The geometry of

ICl_{4}^{-}, ClO_{3}^{-}

and

IBr_{2}^{-}

is square planar, pyramidal and linear respectively.
In the light of the above statements, choose the correct answer from the options given below :

Answer: (D)

Aluminium dissolves in aqueous sodium hydroxide to give the tetrahedral tetrahydroxoaluminate(III) ion,

Na [Al (OH)_{4}]

, and not

[Al (OH)_{6}]^{3 -}

, so Statement-I is false. For Statement-II,

IC l_{4}^{-}

has six electron pairs about iodine (four bonding and two lone pairs),

s p^{3} d^{2}

, with the lone pairs trans, giving a square planar shape;

Cl O_{3}^{-}

has four electron pairs about chlorine (three bonding and one lone pair),

s p^{3}

, giving a trigonal pyramidal shape;

IB r_{2}^{-}

has five electron pairs about iodine (two bonding and three equatorial lone pairs),

s p^{3} d

, giving a linear shape, so Statement-II is true. Statement-I is false but Statement-II is true.

JEE Main · 2026 · 05 Apr 2026 · Shift 2 · Single correct option