Given below are two statements:
Statement-I: The second ionization enthalpy of B, Al and Ga is in the order of B > Al > Ga.
Statement-II: The correct order in terms of first ionization enthalpy is Si < Ge < Pb < Sn.
In the light of the above statements, choose the correct answer from the options given below:
Statement-I: The second ionization enthalpy of B, Al and Ga is in the order of B > Al > Ga.
Statement-II: The correct order in terms of first ionization enthalpy is Si < Ge < Pb < Sn.
In the light of the above statements, choose the correct answer from the options given below:
- (A)Both Statement-I and Statement-II are true.
- (B)Both Statement-I and Statement-II are false.✓ Correct
- (C)Statement-I is true but Statement-II is false.
- (D)Statement-I is false but Statement-II is true.
Answer: (B)
Solution
The second ionization enthalpy removes an electron from the singly charged cation, and for the boron family these values run , since the poor shielding by the intervening electrons makes the second electron of gallium harder to remove than that of aluminium. The order quoted in Statement-I, , is therefore wrong. For the carbon family the first ionization enthalpy decreases down the group with a terminal reversal, giving , the rise at lead arising from the poor shielding of its and electrons. Statement-II reverses this and is also wrong. Both statements are false.
JEE Main · 2026 · 02 Apr 2026 · Shift 2 · Single correct option