If ∑k=1nak=6n3, then ∑k=16(36ak+1−ak)2 is equal to ______.
Answer: 91
Solution
Writing Sn=∑k=1nak=6n3, the general term is an=Sn−Sn−1=6n3−6(n−1)3=6(3n2−3n+1). Then an+1−an=6[(3(n+1)2−3(n+1)+1)−(3n2−3n+1)]=6(6n)=36n, so 36ak+1−ak=k. Therefore ∑k=16(36ak+1−ak)2=∑k=16k2=66⋅7⋅13=91.