JEE Main · 2004 · 24 Apr 2004 · Offline · Chapter_pending

The electrochemical equivalent of a metal is

3.3 \times 1 0^{- 7}

kg per coulomb. The mass of the metal liberated at the cathode when a 3 A current is passed for 2 seconds will be

Answer: (A)

Solution

Faraday's law of electrolysis gives the mass deposited as

m = Z i t

. With

Z = 3.3 \times 1 0^{- 7}

kg/C, a current of

3

A flowing for

2

s liberates

m = 3.3 \times 1 0^{- 7} \times 3 \times 2 = 19.8 \times 1 0^{- 7}

kg.

JEE Main · 2004 · 24 Apr 2004 · Offline · Single correct option