The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double-slit experiment is
- (A)infinite
- (B)five✓ Correct
- (C)three
- (D)zero
Answer: (B)
Solution
Bright fringes in a double-slit pattern obey . With this becomes , and since cannot exceed one, can only take the values . That makes five maxima in all.
JEE Main · 2004 · 24 Apr 2004 · Offline · Single correct option