JEE Main · 2004 · 24 Apr 2004 · Offline · Wave Optics

The angle of incidence at which reflected light totally polarized for reflection from air to glass (refractive index

n

), is

(A) $sin^{- 1} (n)$
(B) $sin^{- 1} (1/ n)$
(C) $tan^{- 1} (1/ n)$
(D) $tan^{- 1} (n)$ ✓ Correct

Answer: (D)

Solution

By Brewster's law the reflected light is completely polarised when it leaves the surface at the polarising angle

i_{p}

fixed by

n = tan i_{p}

. Hence the angle of polarisation is

i_{p} = tan^{- 1} (n)

JEE Main · 2004 · 24 Apr 2004 · Offline · Single correct option

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