When $_{3}\mathrm{Li}^{7}$ nuclei are bombarded by protons, and the resultant nuclei are $_{4}\mathrm{Be}^{8}$, the emitted particles will be

JEE Main · 2006 · 30 Apr 2006 · Offline · Modern Physics

When

_{3} Li^{7}

nuclei are bombarded by protons, and the resultant nuclei are

_{4} Be^{8}

, the emitted particles will be

(A)neutrons
(B)alpha particles
(C)beta particles
(D)gamma photons✓ Correct

Answer: (D)

Solution

Writing the reaction,

_{3} Li^{7} +_{1} H^{1} \to_{4} Be^{8}

, the mass numbers balance (

7 + 1 = 8

) and the charges balance (

3 + 1 = 4

), so no nucleon or charged particle is left over. The energy released in forming the more tightly bound beryllium nucleus is carried away as electromagnetic radiation, that is, a gamma photon.

JEE Main · 2006 · 30 Apr 2006 · Offline · Single correct option

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