JEE Main · 2006 · 30 Apr 2006 · Offline · Current Electricity

The current I drawn from the 5 volt source will be

Answer: (C)

Solution

The resistors in the figure form a bridge-type network fed by the

5 V

source. Working through the series and parallel combinations shown, the network reduces to a single equivalent resistance of

10 Ω

between the terminals of the source. The current drawn then follows from Ohm's law,

I = \frac{V}{R _{eq}} = \frac{5}{10} = 0.5 A

JEE Main · 2006 · 30 Apr 2006 · Offline · Single correct option