JEE Main · 2006 · 30 Apr 2006 · Offline · Conservation of Momentum

A player caught a cricket ball of mass 150 g moving at a rate of

20 m/s

. If the catching process is completed in 0.1 s, the force of the blow exerted by the ball on the hand of the player is equal to

(A)300 N
(B)150 N
(C)3 N
(D)30 N✓ Correct

Answer: (D)

Solution

The ball's momentum changes from

p = m v = 0.15 \times 20 = 3 kg m/s

down to zero as it is caught. The average force is the rate of change of momentum,

F = \frac{Δ p}{Δ t} = \frac{3}{0.1} = 30 N

. By Newton's third law the ball pushes back on the hand with the same magnitude, so the blow felt is

30 N

JEE Main · 2006 · 30 Apr 2006 · Offline · Single correct option

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