The vapour pressure of water at is 17.5 mm Hg. If 18 g of glucose is added to 178.2 g of water at , the vapour pressure of the resulting solution will be
- (A)17.675 mm Hg
- (B)15.750 mm Hg
- (C)16.500 mm Hg
- (D)17.325 mm Hg✓ Correct
Answer: (D)
Solution
By Raoult's law the fractional lowering of vapour pressure equals the mole fraction of the solute. There are of glucose and of water, so the solute mole fraction is . Then gives a lowering of , so the solution's vapour pressure is .
JEE Main · 2008 · 27 Apr 2008 · Offline · Single correct option