The coordination number and the oxidation state of the element ' E ' in the complex [E(en)2(C2O4)]NO2 (where (en) is ethylene diamine) are, respectively,
(A)6 and 2
(B)4 and 2
(C)4 and 3
(D)6 and 3✓ Correct
Answer: (D)
Solution
Ethylenediamine is a bidentate ligand and two of them occupy four coordination sites, while the oxalate ion is also bidentate and occupies two more, so the central element E is surrounded by six donor atoms and its coordination number is six. For the oxidation state, the nitrite ion sits outside the coordination sphere as NO2−, so the complex ion carries a single positive charge; with two neutral en ligands and an oxalate of charge −2, the balance x+(−2)=+1 fixes the oxidation state of E at +3. So the coordination number is six and the oxidation state is three.
JEE Main · 2008 · 27 Apr 2008 · Offline · Single correct option