The area of the region enclosed by the curves y=x,x=e,y=x1 and the positive x-axis is
(A)1 square units
(B)23 square units✓ Correct
(C)25 square units
(D)21 square units
Answer: (B)
Solution
The curves y=x and y=x1 cross at x=1. The region sits below y=x from x=0 to 1 and below y=x1 from x=1 to e, so its area is ∫01xdx+∫1ex1dx=[2x2]01+[lnx]1e=21+1=23 square units.
JEE Main · 2011 · 10 Apr 2011 · Offline · Single correct option