JEE Main · 2012 · 29 Apr 2012 · Offline · Kinematics

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A boy can throw a stone up to a maximum height of 10 m. The maximum horizontal distance that the boy can throw the same stone up to will be

(A) $202 m$
(B)10 m
(C) $102 m$
(D)20 m✓ Correct

Answer: (D)

Solution

Thrown straight up, the stone reaches

h = \frac{u ^{2}}{2 g} = 10

m, which fixes

u^{2} = 20 g

. The greatest horizontal range for a given launch speed comes at a projection angle of

4 5^{\circ}

, where

R_{m a x} = \frac{u ^{2}}{g}

. Substituting

u^{2} = 20 g

gives

R_{m a x} = \frac{20 g}{g} = 20

JEE Main · 2012 · 29 Apr 2012 · Offline · Single correct option

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