JEE Main · 2015 · 04 Apr 2015 · Offline · Surface Chemistry

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3 g

of activated charcoal was added to 50 mL of acetic acid solution ( 0.06 N ) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N . The amount of acetic acid adsorbed (per gram of charcoal) is:

(A)36 mg
(B)42 mg
(C)54 mg
(D)18 mg✓ Correct

Answer: (D)

Solution

The acid that vanished from solution is exactly what the charcoal took up. The normality fell from

0.06

0.042

, a drop of

0.018

N over

50

mL, i.e.

0.018 \times 0.050 = 9 \times 1 0^{- 4}

equivalents removed. Multiplying by the equivalent mass of acetic acid,

60

g, that is

0.054

= 54

mg adsorbed in all. Spread over the

3

g of charcoal, the uptake is

\frac{54}{3} = 18

mg per gram.

JEE Main · 2015 · 04 Apr 2015 · Offline · Single correct option

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