JEE Main · 2019 · 10 Apr 2019 · Shift 1 · Coordination Compounds

The species that can have a trans-isomer is:
(en = ethane-1,2-diamine, ox = oxalate)

(A) $[Pt (en) Cl_{2}]$
(B) $[Pt (en)_{2} Cl_{2}]^{2 +}$ ✓ Correct
(C) $[Cr (en)_{2} (ox)]^{+}$
(D) $[Zn (en) Cl_{2}]$

Answer: (B)

Solution

Geometrical trans-isomerism needs a geometry in which two identical ligands can sit directly opposite one another.

[Pt (en) X_{2} Cl X_{2}] X^{2 +}

is octahedral, and its two chloride ligands can take up trans positions while the two bidentate ethylenediamine ligands fill the remaining four sites. The other species, being square planar with a single en or tetrahedral around

Zn (II)

, cannot place two like ligands trans to each other.

JEE Main · 2019 · 10 Apr 2019 · Shift 1 · Single correct option

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