JEE Main · 2019 · 10 Apr 2019 · Shift 1 · Capacitance

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Figure shows charge (q) versus voltage (V) graph for series and parallel combination of to given capacitors. The capacitances are:

(A) $40 μ F$ and $10 μ F$ ✓ Correct
(B) $50 μ F$ and $30 μ F$
(C) $60 μ F$ and $40 μ F$
(D) $20 μ F$ and $30 μ F$

Answer: (A)

Solution

Since

q = C V

, the slope of a

q

versus

V

line is simply the capacitance. The steeper line therefore belongs to the larger capacitance, the parallel combination, and the gentler line to the smaller, series combination. For capacitors of

40 μ

F and

10 μ

F the parallel value is

40 + 10 = 50 μ

F and the series value is

\frac{40 \times 10}{40 + 10} = 8 μ

F, which is exactly the pair of slopes read off the graph.

JEE Main · 2019 · 10 Apr 2019 · Shift 1 · Single correct option

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