The area (in sq. units) bounded by the parabola y=x2−1, the tangent at the point (2, 3) to it and the y - axis is:
(A)38✓ Correct
(B)332
(C)353
(D)314
Answer: (A)
Solution
The tangent to y=x2−1 at (2,3) has slope dxdy=2x=4, so its equation is y=4x−5. Between the y-axis and x=2 the tangent lies above the parabola, so the enclosed area is ∫02[(4x−5)−(x2−1)]dx=∫02−(x−2)2dx=38.
JEE Main · 2019 · 09 Jan 2019 · Shift 1 · Single correct option