The metal d-orbital that can directly facing the ligands in $\ce{K3[Co(CN)6]}$ are

(B) $d_{x^2-y^2}$ and $d_{z^2}$

(C) $d_{xz}$, $d_{yz}$ and $d_{z^2}$

(D) $d_{xy}$, $d_{xz}$ and $d_{yz}$

JEE Main · 2019 · 12 Jan 2019 · Shift 1 · Coordination Compounds

The metal d-orbital that can directly facing the ligands in

K X_{3} [Co (CN) X_{6}]

are

(A) $d_{x y}$ and $d_{x^{2} - y^{2}}$
(B) $d_{x^{2} - y^{2}}$ and $d_{z^{2}}$ ✓ Correct
(C) $d_{x z}$ , $d_{y z}$ and $d_{z^{2}}$
(D) $d_{x y}$ , $d_{x z}$ and $d_{y z}$

Answer: (B)

Solution

In an octahedral complex the six ligands come in along the

x

y

and

z

axes. The

d

-orbitals whose lobes point straight along those axes are

d_{x^{2} - y^{2}}

, with lobes on the

x

and

y

axes, and

d_{z^{2}}

, with lobes on the

z

axis; these are the

e_{g}

pair that face the ligands directly and feel the strongest repulsion. The other three,

d_{x y}

d_{y z}

and

d_{x z}

, point between the axes. So the orbitals facing the ligands are

d_{x^{2} - y^{2}}

and

d_{z^{2}}

JEE Main · 2019 · 12 Jan 2019 · Shift 1 · Single correct option

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