If the line 3x+4y−24=0 intersects the x-axis at the point A and the y-axis at the point B, then the incentre of the triangle OAB, where O is the origin, is:
(A)(3,4)
(B)(2,2)✓ Correct
(C)(4,3)
(D)(4,4)
Answer: (B)
Solution
The line 3x+4y−24=0 meets the x-axis at A(8,0) and the y-axis at B(0,6), so triangle OAB is right-angled at O with legs OA=8, OB=6 and hypotenuse AB=10. For a right triangle the inradius is r=28+6−10=2, and because the right angle sits at the origin the incentre is at (r,r)=(2,2).
JEE Main · 2019 · 10 Jan 2019 · Shift 1 · Single correct option