Match the thermodynamics processes taking place in a system with the correct conditions. In the table: is the heat supplied, is the work done and is change in internal energy of the system. Match the following:
Process:
(I) Adiabatic
(II) Isothermal
(III) Isochoric
(IV) Isobaric
Condition:
(A)
(B)
(C)
(D)
Process:
(I) Adiabatic
(II) Isothermal
(III) Isochoric
(IV) Isobaric
Condition:
(A)
(B)
(C)
(D)
- (A)(I) → (B); (II) → (D); (III) → (A); (IV) → (C)✓ Correct
- (B)(I) → (A); (II) → (A); (III) → (B); (IV) → (C)
- (C)(I) → (A); (II) → (B); (III) → (D); (IV) → (D)
- (D)(I) → (B); (II) → (A); (III) → (D); (IV) → (C)
Answer: (A)
Solution
In an adiabatic process no heat is exchanged, so . In an isothermal process the temperature is fixed, so for an ideal gas the internal energy is unchanged and . In an isochoric process the volume is fixed, so no work is done and . In an isobaric process heat flows, the gas does work and its temperature changes, so , and are all non-zero. Hence the adiabatic process pairs with , the isothermal with , the isochoric with and the isobaric with all three quantities non-zero.
JEE Main · 2020 · 04 Sep 2020 · Shift 2 · Single correct option