In the circuit shown in the figure, the total charge is 750 $\mu \mathrm{C}$ and the voltage across capacitor $\mathrm{C}_{2}$ is 20 V. Then the charge on capacitor $\mathrm{C}_{2}$ is

JEE Main · 2020 · 03 Sep 2020 · Shift 1 · Capacitance

In the circuit shown in the figure, the total charge is 750

μ C

and the voltage across capacitor

C_{2}

is 20 V. Then the charge on capacitor

C_{2}

(A) $160 μ C$
(B) $650 μ C$
(C) $590 μ C$ ✓ Correct
(D) $450 μ C$

Answer: (C)

Solution

The capacitor network draws a fixed total charge of

750 μ

C from the source, and this charge divides among the branches according to how they are connected. With the potential difference across

C_{2}

fixed at the measured

20

V, the charge held on the rest of the network alongside it accounts for

160 μ

C, so by conservation of charge the amount left on

C_{2}

750 - 160 = 590 μ

JEE Main · 2020 · 03 Sep 2020 · Shift 1 · Single correct option

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