The area (in sq. units) of the region {(x,y)∈R2≤y≤3−2x}, is
(A)332✓ Correct
(B)329
(C)331
(D)334
Answer: (A)
Solution
The region lies between the parabola y=x2 below and the line y=3−2x above. They meet where x2=3−2x, i.e. x2+2x−3=0, at x=−3 and x=1. The area is ∫−31[(3−2x)−x2]dx=[3x−x2−3x3]−31=35−(−9)=332.
JEE Main · 2020 · 08 Jan 2020 · Shift 2 · Single correct option