For the Balmer series in the spectrum of H atom, the correct statements among (I) to (IV) are :
(I) As wavelength decreases, the lines in the series converge
(II) The integer n 1 is equal to 2
(III) The lines of longest wavelength corresponds to
(IV) The ionization energy of hydrogen can be calculated from wave number of these lines
(I) As wavelength decreases, the lines in the series converge
(II) The integer n 1 is equal to 2
(III) The lines of longest wavelength corresponds to
(IV) The ionization energy of hydrogen can be calculated from wave number of these lines
- (A)(II), (III), (IV)
- (B)(I), (III), (IV)
- (C)(I), (II), (III)✓ Correct
- (D)(I), (II), (IV)
Answer: (C)
Solution
For the Balmer series the lines crowd together toward the series limit as the wavelength shortens and the wavenumber grows, so that statement is true; the series has its lower level at , so that one is true as well; and the longest wavelength belongs to the smallest-energy jump, the transition, so it too is true. The claim that ionization energy is read directly from a Balmer line is false, since ionization corresponds to a transition reaching . Thus the first three statements hold.
JEE Main · 2020 · 08 Jan 2020 · Shift 1 · Single correct option