The stoichiometry and solubility product of a salt with the solubility curve given below is, respectively:
(A)XY,2×10−5M3
(B)XY3,1×10−9M3
(C)XY2,4×10−9M3✓ Correct
(D)X2Y,2×10−9M3
Answer: (C)
Solution
Reading the solubility values as [X2+]=10−3 M and [Y−]=2×10−3 M for the salt XY2, which dissolves as XY2→X2++2Y−, the solubility product is Ksp=[X2+][Y−]2=(10−3)(2×10−3)2=4×10−9M3.
JEE Main · 2020 · 08 Jan 2020 · Shift 1 · Single correct option