JEE Main · 2020 · 07 Jan 2020 · Shift 2 · Current Electricity

In the figure, potential difference between A and B is:

Answer: (B)

Solution

Both diodes are forward biased, so treat each as a plain wire. The network then reduces to a

5 Ω

and a

10 Ω

resistor in series across the

30

V supply, and the potential difference between A and B is the share the divider drops,

V_{A B} = \frac{30}{5 + 10} \times 5 = 10

JEE Main · 2020 · 07 Jan 2020 · Shift 2 · Single correct option