1-methyl ethylene oxide when treated with an excess of HBr, produces
(A)(see structure)
(B)(see structure)
(C)(see structure)
(D)(see structure)✓ Correct
Answer: (D)
Solution
Propylene oxide (1-methylethylene oxide) is protonated on oxygen by HBr, and bromide then opens the strained ring. With excess HBr the newly formed alcohol is also converted to a bromide, so both ring carbons end up bearing bromine, giving CH3CHBrCH2Br, 1,2-dibromopropane.
JEE Main · 2020 · 07 Jan 2020 · Shift 1 · Single correct option